Table of Contents -

**Simplification Questions**

In Simplification Questions, an individual needs to solve the problem by doing complex calculations. Here, on this page we have mentioned Simplification Formulas as well as **Simplification Questions **& Answers that contains short solutions and can be solved using tricks.

Simplification Topic comes under Quantitative Aptitude section and is asked in mostly all the competitive exams. So, it’s important for candidates to learn the tricks and tactics of solving Simplification Questions in the given time limit.

**Rules of Simplification:**

__VBODMAS__:

- V : Virnaculum or bar
- B : Bracket
- : Of
- D : Division
- M : Multiplication
- A : Addition
- S : Subtraction

__Modulus__:

Modulus of a real number x is its positive value, denoted by |x|.

Thus, |7| = 7 and |−7| = 7

**Simplification Formula:**

- (a + b)
^{2}= a^{2}+ b^{2}+ 2ab - (a − b)
^{2}= a^{2}+ b^{2}− 2ab - (a + b)(a − b) = a
^{2}− b^{2} - (a + b)
^{2}− (a − b)^{2}= 4ab - (a + b)
^{2}+ (a − b)^{2}= 2 (a^{2}+ b^{2}) - (a + b + c)
^{2}= a^{2}+ b^{2}+ c^{2}+ 2 (ab + bc + ac) - (a
^{3}+ b^{3}) = (a + b) (a^{2}− ab + b^{2}) - (a
^{3}− b^{3}) = (a − b) (a^{2}+ ab + b^{2}) - (a + b)
^{3}= a^{3}+ b^{3}+ 3ab(a + b) - (a − b)
^{3}= a^{3}− b^{3}− 3ab(a − b) - (a
^{3}+ b^{3}+ c^{3}− 3abc) = (a + b + c) (a^{2}+ b^{2}+ c^{2}− (ab + bc + ca)) - If a + b + c = 0, then a
^{3}+ b^{3}+ c^{3}= 3abc

**Simplification Tricks:**

- Learn BODMAS.
- Use the concept of digital sum.
- Memorize tables up to 30.
- Memorize cubes and squares of numbers up to 35.
- Learn the concept of percentages.
- Learn tricks to find squares and cubes of numbers greater than 35.
- Learn tricks to find cube roots and square roots of large number.
- Memorize the reciprocals.

Get Here: __How to Prepare for Written Exam__

**Simplification Questions**

**Simplification Questions and Answers**

**Question 1)** 1035 ÷ [(3/4) of (71 + 65) – 15 ¾] = ?

- 12
- 24
- 18
- 26
- None of these

**Answer:** (1)

__Explanation__:

1035 ÷ [(3/4)*136 – 63/4] = x

X = 1035 ÷ [102 – (63/4)]

X = 1035 ÷ [(408 – 63)/4]

X = 1035 ÷ (345/4)

X = 1035 *4/345

X = 12

**Question 2)** √((27 ÷ 5 ×?) ÷ 15) = 5.4 ÷ 6 +0.3

- 12
- 4
- 9
- 15
- None of these

**Answer:** (2)

__Explanation__:

√((27 /5 )×(x/15)) =0.9+0.3

(3/5) √ x = 1.2

√ x = 6/3 =2

X= 4

**Question 3)** 36^{3} × 4096^{1/2} × 72 × 18 ÷ (93 × 722) = 4?

- 8
- 12
- 7
- 5
- None of these

**Answer:** (4)

__Explanation__:

(36*36*36*64*72*18)/(9*9*9*72*72) = 4^{x}

4*4*4^{3} = 4^{x}

4^{5} = 4^{x}

X = 5

**Question 4)** (913 + 329 + 522 + 343) ÷ (18 + 24 – ? + 18) = 43

- 23
- 11
- 7
- 29
- 15

**Answer:** (2)

__Explanation__:

(913 + 329 + 522 + 343) ÷ (18 + 24 – x + 18) = 43

2107 ÷ (60 –x) = 43

(2107/43) = 60 – x

49 = 60 – x

X = 60 – 49 = 11

**Question 5)** 12¾ % of 2400 + 23 ½ % of 800 + 452 = 1125 ÷ 25 × 4 + ?

- 658
- 532
- 776
- 614
- 590

**Answer:** (3)

__Explanation__:

(51/400)*2400 + (47/200)*800 + 2025 = (1125/25) + 4x

306 + 818 + 2025 – 45 = 4x

3104 = 4x

X = 3104/4 = 776

**Question 6)** (4/5) of 11325 + 56 % of 1750 = (?)^{2} + 436

- 116
- 72
- 98
- 84
- 102

**Answer:** (3)

__Explanation__:

(4/5)*11325 + (56/100)*1750 = x^{2} + 436

9060 + 980 – 436 = x^{2}

10040 – 436 = x^{2}

9604 = x^{2}

X = 98

**Question 7)** 1.8 × 625 + 5.6 ÷ 0.7 + 415 × 11.8 = (?)^{2} – 211

- 79
- 85
- 92
- 69
- 61

**Answer:** (1)

__Explanation__:

1.8 × 625 + 5.6 ÷ 0.7 + 415 × 11.8 = (?)^{2} – 211

1125 + 8 + 4897 = x^{2} – 211

6241 = x^{2}

X = 79

**Question 8) **586 × 9234 ÷ 48 % of 950 = 36 × 750 ÷ 4 + ? + 4500

- 25
- 728
- 5
- 75
- 474

**Answer:** (3)

__Explanation__:

586 × [9234 ÷ ((48/100)*950)] = 36 × (750/4) + x + 4500

586*(9234/456) = 6750 + x + 4500

11866.5 – 11250

X = 616.5

**Question 9) **(28 × 9 + 54 × 3 + 12 × 11) ÷ (142 – √961 + 17) = ?

- 6
- 3
- 5
- 8
- 7

**Answer:** (2)

__Explanation__:

(28 × 9 + 54 × 3 + 12 × 11) ÷ (14^{2 }– √961 + 17) = x

X = (252 + 162 + 132) ÷ (196 – 31 + 17)

X = 546/182

X = 3

**Question 10) **√13225 + ∛205379 + 52 % of 700 = 408 + ?

- 156
- 218
- 189
- 130
- None of these

**Answer:** (4)

__Explanation__:

√13225 + ∛205379 + 52 % of 700 = 408 + x

115 + 59 + (52/100)*700 – 408 = x

115 + 59 + 364 – 408 = x

X = 130

**Question 11) **(7 × 7)^{3} ÷ (49 × 7)^{3} × (2401)^{2} = 7^{?}

- 7
- 5
- 6
- 8
- None of these

**Answer:** (2)

__Explanation__:

(7 × 7)^{3} ÷ (49 × 7)^{3} × (2401)^{2} = 7^{x}

(7^{2})^{3} ÷ (7^{2} × 7)^{3} × (7^{4})^{2} = 7^{x}

7^{6} ÷ 7^{9} × 7^{8} = 7^{x}

7^{6 – 9 + 8 }= 7^{x}

7^{5} = 7^{x}

X = 5

**Question 12) **5 ¾ – 4 1/8 + 7 ½ – 3 3/8 = ?

- 4 3/7
- 6 5/6
- 7 ½
- 5 ¾
- None of these

**Answer:** (4)

__Explanation__:

5 ¾ – 4 1/8 + 7 ½ – 3 3/8 = x

X = (5 – 4 + 7 – 3) (3/4 – 1/8 + ½ – 3/8)

X = 5 [(6 – 1 + 4 – 3)/8]

X = 5 (6/8) = 5 (3/4)

**Question 13)** (2 7/9) ÷ (5 1/2) × (693/350) = (1/3) of (5/7) of (147/175) of (?)

- 12
- 26
- 5
- 18
- 9

**Answer:** (3)

__Explanation__:

(25/9)*(2/11)*(693/350) = (1/3)*(5/7)*(147/175)*x

1 = (x/5)

X = 5

Read Out: __Problem on HCF and LCM__

**Question 14)** (3/7) of ? – (2/5) of (13/16) of 2160 = 12 % of 900

- 2150
- 1540
- 1960
- 1890
- 2370

**Answer:** (4)

__Explanation__:

(3/7)*x – (2/5)*(13/16)*2160 = (12/100)*900

(3x/7) – 702 = 108

(3x/7) = 108 + 702

(3x/7) = 810

X = (810*7/3) = 1890

**Question 15)** ∛157464 + √8836 – 45 % of 800 =? + (1188 ÷ 9) – 36^{2}

- 952
- 816
- 878
- 924
- None of these

**Answer:** (1)

__Explanation__:

54 + 94 – (45/100)*800 = x + (1188/9) – 1296

54 + 94 – 360 + 1296 = x + 132

54 + 94 – 360 + 1296 – 132 = x

X = 952

**Question 16)** (4/5) of 11325 + 56 % of 1750 = (?)^{2} + 436

- 116
- 72
- 98
- 84
- 102

**Answer:** (3)

__Explanation__:

(4/5)*11325 + (56/100)*1750 = x^{2} + 436

9060 + 980 – 436 = x^{2}

10040 – 436 = x^{2}

9604 = x^{2}

X = 98

**Question 17)** 18 ¼ % of 17200 + 33 2/3 % of 1860 + 37 2/3 % of 19680 = ?

- 11178
- 13456
- 9824
- 10242
- 8454

**Answer:** (1)

__Explanation__:

(73/400)*17200 + (101/300)*1860 + (113/300)*19680= x

X = 3139 + 626.2 + 7412.8

X = 11178

**Question 18)** 1323 ÷ (27 % of 700) = 35 × 7 3/5 of (? ÷ 190)

- 7
- 9
- 4
- 5
- 8

**Answer:** (4)

__Explanation__:

1323 ÷ [(27/100)*700] = 35 × (38/5)*(x/190)

1323 ÷ 189 = 35 × (38/5)*(x/190)

(7*5*190)/(35*38) = x

X = 5

**Question 19)** 32450 ÷ 11 + (4/9) of 11520 + 48 % of 7500 = ?^{2} – 430

- 150
- 178
- 110
- 92
- None of these

**Answer:** (3)

__Explanation__:

(32450/11) + (4/9)*11520 + (48/100)*7500 = x^{2} – 430

2950 + 5120 + 3600 + 430 = x^{2}

X^{2} = 12100

X = 110

Solve Here: __Discount Questions and Answers__

**Question 20)** 49^{2} ÷ 14 × 8 + 582 = 4 × ? – 15 % of 2480

- 1489
- 1277
- 1645
- 1823
- None of these

**Answer:** (2)

__Explanation__:

(49*49*8)/14 + 58^{2} = 4x – (15/100)*2480

1372 + 3364 = 4x – 372

1372 + 3364 + 372 = 4x

5108 = 4x

X = 5108/4 = 1277

Candidates must go through Simplification Questions & Answers given on this page of recruitmentresult.com and can practice from it to score good marks in the examination.